Vectors

    OCR
    A-Level
    Mathematics

    Master the geometry and algebra of 3D space with this guide to A-Level Vectors. We will break down complex proofs and mechanics problems into manageable steps, ensuring you can secure every mark available for this crucial topic."

    5
    Min Read
    3
    Examples
    5
    Questions
    0
    Key Terms
    🎙 Podcast Episode
    Vectors
    0:00-0:00

    Study Notes

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    Overview

    Vectors are a fundamental concept in mathematics, representing quantities that possess both magnitude (size) and direction. Unlike scalars (like mass or temperature), vectors provide a powerful tool for describing movement and forces in two and three dimensions. For OCR A-Level candidates, a deep understanding of vectors is essential, as it forms a bridge between pure mathematics and mechanics. Typical exam questions range from geometric proofs involving collinearity and intersecting lines to modelling real-world scenarios like the motion of a particle in 3D space. Mastery of vector notation (both column and i, j, k form), manipulation, and geometric interpretation is key to earning high marks.

    vectors_podcast.mp3

    Key Concepts

    1. Vector Notation and Representation

    A vector can be represented in several ways, and candidates must be fluent in converting between them.

    • Column Vector: e.g., (3, -1, 4) represents a displacement of 3 units along the x-axis, -1 along the y-axis, and 4 along the z-axis.
    • i, j, k Notation: The same vector can be written as 3i - j + 4k, where i, j, and k are unit vectors (magnitude 1) in the positive x, y, and z directions, respectively.
    • Handwritten Form: In exams, it is crucial to distinguish vectors from scalars. This is done by underlining the vector name (e.g., a) or drawing an arrow above it.

    2. Position and Displacement Vectors

    This is a common area of confusion, but the distinction is vital.

    • Position Vector: A vector that starts at the origin (O) and ends at a specific point (P). It is denoted as OP or simply p. It defines the position of P in space.
    • Displacement Vector: A vector that represents the journey from one point (A) to another (B). It is denoted AB and is calculated using the formula: AB = b - a, where a and b are the position vectors of A and B. Credit is given for this correct formulation.

    3d_vector_geometry.png

    3. Magnitude of a Vector

    The magnitude (or modulus) of a vector is its length. For a vector v = ai + bj + ck, its magnitude |v| is found using Pythagoras' Theorem in 3D.

    Example: For vector v = 3i - 4j + 5k, the magnitude is |v| = sqrt(3^2 + (-4)^2 + 5^2) = sqrt(9 + 16 + 25) = sqrt(50) = 5 * sqrt(2). An M1 mark is typically awarded for a correct method.

    4. Vector Operations

    Basic arithmetic operations have geometric interpretations.

    • Addition: a + b is found by placing the vectors head-to-tail. The resultant vector goes from the start of a to the end of b.
    • Subtraction: a - b is equivalent to a + (-b). Geometrically, if a and b start from the same point, a - b is the vector from the end of b to the end of a.
    • Scalar Multiplication: Multiplying a vector by a scalar k changes its magnitude by a factor of |k|. If k is negative, the vector's direction is reversed. Two vectors a and b are parallel if and only if a = kb for some non-zero scalar k.

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    5. Geometric Proofs

    Vectors are a powerful tool for proving geometric properties. A classic exam question involves proving that three points (A, B, C) are collinear (lie on the same straight line).

    Method for Collinearity: To prove A, B, and C are collinear, you must:

    1. Find two displacement vectors, e.g., AB and BC.
    2. Show they are parallel by demonstrating that one is a scalar multiple of the other (e.g., AB = k * BC).
    3. State that they share a common point (in this case, B).
    4. Conclude that because they are parallel and share a common point, A, B, and C must be collinear. An E1 mark is awarded for this final, rigorous conclusion.

    collinearity_proof.png

    Mathematical Relationships

    Formula/RelationshipDescriptionStatus
    Displacement Vector ABb - aMust memorise
    Magnitude `v=
    Parallel Vectorsa = kb for scalar kMust memorise
    Collinearity of A, B, CAB = k * BC AND common point BMust memorise
    Vector Equation of a Liner = a + t * dGiven on formula sheet
    Scalar (Dot) Product`a . b =a

    Practical Applications

    Vectors are not just an abstract concept; they are essential in many fields:

    • Physics and Engineering: Modelling forces, velocity, and acceleration. For example, calculating the resultant force on a bridge or the trajectory of a projectile.
    • Computer Graphics: Used extensively in 3D modelling and animation to determine the position and orientation of objects in virtual space.
    • Navigation: GPS systems use vectors to represent location and displacement to calculate routes and travel times.

    Worked Examples

    3 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    Given the vector p = 2i - 6j + 3k, calculate its magnitude.

    2 marks
    foundation

    Hint: Remember the 3D version of Pythagoras' theorem.

    Q2

    The vectors a = 3i + mj and b = 6i - 8j are parallel. Find the value of m.

    3 marks
    standard

    Hint: If two vectors are parallel, one must be a scalar multiple of the other.

    Q3

    OABC is a parallelogram. The position vector of A is a and the position vector of C is c. Find the position vector of the midpoint of the diagonal OB.

    4 marks
    standard

    Hint: In a parallelogram, the diagonals bisect each other. First find the position vector of B.

    Q4

    The vector equation of two lines are r1 = (2i + j) + t(i - 3j) and r2 = (i - 2j) + s(2i + j). Find the position vector of their point of intersection.

    5 marks
    challenging

    Hint: At the point of intersection, `r1 = r2`. Equate the `i` and `j` components to form simultaneous equations.

    Q5

    A particle starts from rest. It moves with constant acceleration a = (2i - 3j) m/s^2. Find its speed after 4 seconds.

    4 marks
    challenging

    Hint: Use the vector form of the `suvat` equation `v = u + at`. Remember that 'speed' is the magnitude of the velocity.

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