Balancing Equations — Edexcel GCSE study guide illustration

    Balancing Equations

    Edexcel
    GCSE
    Chemistry

    Master the core skill of balancing chemical equations for your Edexcel GCSE Chemistry exam. This guide breaks down the Law of Conservation of Mass and provides a foolproof step-by-step method to secure every mark, turning a tricky topic into a simple puzzle.

    4
    Min Read
    3
    Examples
    5
    Questions
    6
    Key Terms
    🎙 Podcast Episode
    Balancing Equations
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    Study Notes

    Header image for Balancing Equations

    Overview

    Balancing chemical equations is a fundamental skill in chemistry, underpinning all quantitative analysis. It is the practical application of one of the most important laws in science: the Law of Conservation of Mass. In any chemical reaction, atoms are not created or destroyed; they are simply rearranged. A balanced symbol equation is a representation of this, showing the exact same number of atoms of each element on both the reactant (left) and product (right) sides. For your Edexcel GCSE, examiners will test your ability to balance equations in a variety of contexts, from simple synthesis reactions to more complex combustion and displacement reactions. Mastery of this topic is crucial as it forms the foundation for reacting mass calculations, mole concepts, and stoichiometry, which are heavily weighted in the exam.

    Podcast: Mastering Balancing Equations for GCSE Chemistry

    Key Concepts

    Concept 1: The Law of Conservation of Mass

    This law states that mass is conserved in a closed system. When you see a chemical equation, you are seeing a model of this law in action. The total mass of all the reactants must equal the total mass of all the products. To achieve this, we must have the same number and type of atoms before and after the reaction arrow. If you start with 2 atoms of hydrogen, you must end with 2 atoms of hydrogen. They might be bonded to different elements, but they are still there.

    Example: In the reaction 2H₂ + O₂ → 2H₂O, the mass of two hydrogen molecules plus one oxygen molecule is exactly equal to the mass of two water molecules.

    Concept 2: Coefficients vs. Subscripts

    This is the most critical distinction to understand.

    • Subscripts (the small numbers like the '2' in H₂O) tell you how many atoms are in a single molecule. You CANNOT change these. Altering a subscript changes the chemical identity of the substance (e.g., changing H₂O to H₂O₂ turns water into hydrogen peroxide, a completely different chemical).
    • Coefficients (the large numbers in front of a formula, like the '2' in 2H₂O) tell you how many of that entire molecule or formula unit you have. This is the ONLY thing you are allowed to change when balancing an equation.

    Concept 3: The Systematic Approach (M-N-H-O Rule)

    To avoid getting into a loop of changing coefficients back and forth, a systematic approach is essential. A reliable method is to balance elements in the following order:

    1. Metals
    2. Non-metals (excluding Hydrogen and Oxygen)
    3. Hydrogen
    4. Oxygen

    This works because hydrogen and oxygen often appear in multiple reactants and products, so leaving them until last makes the final balancing step much simpler.

    A visual guide to balancing chemical equations.

    Mathematical/Scientific Relationships

    The core relationship is simple:

    Total atoms of Element X on reactant side = Total atoms of Element X on product sideTo calculate the number of atoms, you use the formula:

    Number of atoms = Coefficient × SubscriptFor compounds with brackets, like Ca(NO₃)₂, remember to multiply the subscript outside the bracket by the subscript of each element inside the bracket.

    • Nitrogen atoms = 1 (Ca) × 1 (coefficient, implied) × 2 (bracket subscript) = 2
    • Oxygen atoms = 1 (Ca) × 1 (coefficient, implied) × 3 (O subscript) × 2 (bracket subscript) = 6

    Practical Applications

    Balancing equations is not just an academic exercise; it is vital in the real world. For example, in the pharmaceutical industry, chemists must use balanced equations to calculate the exact amounts of reactants needed to produce a specific quantity of a drug, ensuring purity and avoiding waste. In manufacturing, such as the Haber process for making ammonia (N₂ + 3H₂ → 2NH₃), balanced equations are used to optimize the reaction conditions and maximize the yield of the product, which is a key ingredient in fertilizers that help feed the world.

    Worked Examples

    3 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    Balance the equation: Al + HCl → AlCl₃ + H₂

    3 marks
    standard

    Hint: Start with the Aluminium Chloride (AlCl₃). Remember that hydrogen exists as H₂.

    Q2

    Write a balanced symbol equation for the reaction between sodium carbonate (Na₂CO₃) and nitric acid (HNO₃) to produce sodium nitrate (NaNO₃), water (H₂O), and carbon dioxide (CO₂).

    3 marks
    standard

    Hint: This is a classic acid-carbonate reaction. Balance the sodium atoms first.

    Q3

    Balance the ionic equation for the reaction between chlorine and bromide ions: Cl₂ + Br⁻ → Cl⁻ + Br₂

    2 marks
    challenging

    Hint: This is a Higher Tier question. You must balance both the atoms AND the total charge on each side.

    Q4

    Balance the equation for the decomposition of lead(II) nitrate, which produces lead(II) oxide, nitrogen dioxide, and oxygen. Pb(NO₃)₂ → PbO + NO₂ + O₂

    4 marks
    challenging

    Hint: This is a tricky one. Balance the Pb first, then the N. You will likely need to adjust coefficients multiple times.

    Q5

    A student writes the following equation for the reaction of potassium with water: K + H₂O → K₂O + H₂. Identify the errors in the student's equation and write the correct balanced equation.

    3 marks
    standard

    Hint: What is the correct product when an alkali metal reacts with water?

    Key Terms

    Essential vocabulary to know

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