Probability

    Master OCR Further Maths Probability by tackling conditional events, algebraic tree diagrams, and quadratic equation formation. This guide provides examiner insights, worked examples, and memory hooks to help you secure top marks on this high-stakes topic.

    5
    Min Read
    3
    Examples
    5
    Questions
    6
    Key Terms
    🎙 Podcast Episode
    Probability
    11:32
    0:00-11:32

    Study Notes

    Header image for OCR GCSE Further Mathematics: Probability.

    Overview

    Welcome to the definitive guide for Probability (5.4) in the OCR GCSE Further Mathematics specification. This topic is a cornerstone of the exam, blending pure probability theory with advanced algebraic manipulation. Unlike standard GCSE, you will be required to move beyond simple probability trees and engage with conditional probability in 'without replacement' scenarios, which often leads to forming and solving quadratic equations. Examiners frequently use this topic to test multiple Assessment Objectives simultaneously, particularly AO2 (Reasoning) and AO3 (Problem Solving), which together account for 70% of the marks. A strong command of this area is not just about earning marks; it's about developing a sophisticated mathematical mindset that connects different areas of the curriculum. This guide will equip you with the core concepts, examiner-approved techniques, and multi-modal resources to achieve excellence.

    Listen to our 10-minute audio guide on Probability.

    Key Concepts

    Concept 1: Conditional Probability and 'Without Replacement'

    This is the single most important concept to master. When an event occurs 'without replacement', the outcome of the second event is dependent on the outcome of the first. This is the essence of conditional probability. The total number of possible outcomes decreases for the second event, which is a common source of error for candidates.

    The Golden Rule: In any 'without replacement' problem, the denominator of the probabilities for the second event MUST be one less than the denominator for the first event. Forgetting this is the most frequent mistake and will lose you the initial method marks.

    Example: A bag contains 5 red and 3 blue balls (8 total). A ball is picked and not replaced. A second ball is picked.

    • P(First is Red) = 5/8
    • P(Second is Red, GIVEN the first was Red) = 4/7 (There are now only 4 red balls and 7 total balls left).

    Correct structure for an algebraic 'without replacement' tree diagram.

    Concept 2: The Core Probability Rules

    The entire topic rests on two fundamental rules for combining probabilities, which are best visualised using a tree diagram.

    1. The AND Rule (Multiplication): To find the probability of a sequence of events occurring one after another (e.g., picking a red ball AND then a blue ball), you multiply the probabilities along the corresponding branches of the tree diagram. Think of it as travelling along a single path from start to finish.

      • P(A and B) = P(A) * P(B|A)
    2. The OR Rule (Addition): To find the probability of an overall outcome that can be achieved in more than one way (e.g., picking one ball of each colour), you add the probabilities of the individual, mutually exclusive paths. First, calculate the probability of each complete path (using the AND rule), then sum the results.

      • P(one of each) = P(Red then Blue) + P(Blue then Red)

    A summary of the essential probability rules you need to know.

    Concept 3: Algebraic Probability

    This is the hallmark of Further Mathematics. Questions will introduce an unknown, 'x', representing the number of items of a certain type. Your task is to build a probability tree using algebraic fractions and then form an equation using information given in the question. This almost always results in a quadratic equation that you must solve.

    Process:

    1. Define your probabilities algebraically on the tree diagram (e.g., P(Red) = x/N).
    2. Identify the outcome path(s) described in the question.
    3. Multiply along the branches to form an algebraic expression for the probability of that outcome.
    4. Set this expression equal to the probability value given in the question.
    5. Solve the resulting equation (usually quadratic). Remember to discard any solutions that are not valid in the context (e.g., negative numbers of balls, or a number greater than the total).

    Mathematical Relationships

    • Conditional Probability Formula: P(B|A) = P(A and B) / P(A). This states the probability of B happening given A has already happened. It is the foundation of the 'without replacement' logic. (Must memorise)
    • The Complement Rule: P(At least one) = 1 - P(None). This is a crucial time-saving technique. For example, the probability of picking at least one red ball is 1 minus the probability of picking no red balls (i.e., all blue balls). (Must memorise)
    • Sum of Probabilities: For any event, P(A) + P(not A) = 1. On a tree diagram, the sum of probabilities on branches originating from a single point must always equal 1. (Given on formula sheet)

    Practical Applications

    While the exam questions focus on abstract scenarios like coloured balls or counters, the principles of conditional probability are fundamental to many real-world fields. Actuaries in the insurance industry use it to calculate risk based on a series of events. In medical testing, it's used to determine the accuracy of a diagnosis given a particular test result (the probability of having a disease given a positive test). It is also the mathematical basis for machine learning algorithms used in spam filtering and recommendation systems.

    Visual Resources

    2 diagrams and illustrations

    Correct structure for an algebraic 'without replacement' tree diagram.
    Correct structure for an algebraic 'without replacement' tree diagram.
    A summary of the essential probability rules you need to know.
    A summary of the essential probability rules you need to know.

    Interactive Diagrams

    2 interactive diagrams to visualise key concepts

    WithoutWithYesNoYesNoStart: Read QuestionWith or Without Replacement?Draw Tree: Reduce Denominator on 2nd StageDraw Tree: Keep Denominator SameAlgebraic (x)?Form Equation from Given ProbabilityIdentify Paths for Desired OutcomeSolve Quadratic & Reject Invalid SolutionsMultiply Along PathsMultiple Paths?Add Path ProbabilitiesState Final ProbabilityState Final Value of x

    A flowchart detailing the step-by-step process for solving OCR Further Maths probability questions.

    Problem TypesProbability CoreFoundation forUsed withRequiresRequiresSolved usingRequiresConditional ProbabilityWithout ReplacementAND Rule: MultiplyOR Rule: AddAlgebraic ProbabilityQuadratic EquationsMixed Outcomes

    A concept map showing the relationships between the key ideas in Further Maths Probability.

    Worked Examples

    3 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    A box contains 5 red and 4 green pens. A pen is chosen at random and not replaced. A second pen is then chosen. Calculate the probability that at least one of the pens is green.

    4 marks
    standard

    Hint: Consider using the complement rule. What is the only outcome where you DON'T have at least one green pen?

    Q2

    There are 'x' counters in a bag. 6 of the counters are red and the rest are white. Two counters are taken from the bag at random. The probability that both counters are red is 1/3. Find the value of 'x'.

    5 marks
    challenging

    Hint: The total number of counters is 'x'. Set up the algebraic fractions for picking two red counters without replacement.

    Q3

    On a school trip, students can choose one activity: kayaking (K) or climbing (C). The probability a student is in Year 10 is 0.6. The probability a Year 10 student chooses kayaking is 0.7. The probability a Year 11 student chooses kayaking is 0.4. Find the probability that a randomly chosen student is in Year 11 and chooses climbing.

    3 marks
    standard

    Hint: First, find the probability a student is in Year 11. Then find the probability a Year 11 student chooses climbing.

    Q4

    A biased coin has P(Heads) = 1/3. The coin is flipped twice. What is the probability of getting one Head and one Tail?

    3 marks
    foundation

    Hint: This can happen in two orders: Head then Tail, or Tail then Head. Calculate both.

    Q5

    In a group of 30 students, 18 have a laptop and 15 have a tablet. 6 students have neither. A student is chosen at random. Find the probability that the student has both a laptop and a tablet.

    4 marks
    challenging

    Hint: This is a Venn diagram or set theory problem disguised as probability. Find how many students have at least one device first.

    Key Terms

    Essential vocabulary to know

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